|Gashimov Memorial (2019)|
Shamkir Chess 2019 was a 10-player single round-robin held in memory of Vugar Gashimov. The 6th edition of the tournament in Shamkir, Azerbaijan ran from 31 March to 9 April and featured World Champion Magnus Carlsen. The total prize fund was 100,000 euros, with 30,000 euros for first place. Players received 120 minutes for the first 40 moves, 60 minutes for the next 20 moves and then 15 minutes for the rest of the game, with a 30 seconds per move increment starting from move 61. A rapid playoff would take place in case of a tie for first place. (1)
Carlsen won the event for the 4th time, with 7/9 and 2991 performance.
Official site: http://shamkirchess.com/. ChessBase: https://en.chessbase.com/post/shamk... Chess.com: https://www.chess.com/news/view/sha... TWIC: http://theweekinchess.com/chessnews...
Previous edition: Gashimov Memorial (2018)
Elo 1 2 3 4 5 6 7 8 9 0
1 Carlsen 2845 * ˝ 1 1 1 ˝ ˝ 1 ˝ 1 7
2 Ding Liren 2812 ˝ * ˝ 1 ˝ ˝ 1 0 ˝ ˝ 5
3 Karjakin 2753 0 ˝ * ˝ 1 ˝ ˝ ˝ ˝ 1 5
4 Grischuk 2771 0 0 ˝ * ˝ ˝ 1 1 ˝ ˝ 4˝
5 Anand 2779 0 ˝ 0 ˝ * ˝ ˝ ˝ 1 1 4˝
6 Radjabov 2756 ˝ ˝ ˝ ˝ ˝ * ˝ ˝ ˝ ˝ 4˝
7 Topalov 2740 ˝ 0 ˝ 0 ˝ ˝ * ˝ 1 ˝ 4
8 Navara 2739 0 1 ˝ 0 ˝ ˝ ˝ * ˝ ˝ 4
9 Mamedyarov 2790 ˝ ˝ ˝ ˝ 0 ˝ 0 ˝ * ˝ 3˝
10 Giri 2797 0 ˝ 0 ˝ 0 ˝ ˝ ˝ ˝ * 3
(1) chess24: Gashimov Memorial 2019 https://chess24.com/en/watch/live-t...
| page 1 of 2; games 1-25 of 45
|1. Anand vs Navara
||½-½||41||2019||Gashimov Memorial||B90 Sicilian, Najdorf|
|2. A Giri vs Topalov
|| ||½-½||50||2019||Gashimov Memorial||C65 Ruy Lopez, Berlin Defense|
|3. Radjabov vs Carlsen
||½-½||41||2019||Gashimov Memorial||C55 Two Knights Defense|
|4. Karjakin vs Ding Liren
||½-½||24||2019||Gashimov Memorial||C53 Giuoco Piano|
|5. Grischuk vs Mamedyarov
|| ||½-½||37||2019||Gashimov Memorial||C67 Ruy Lopez|
|6. A Giri vs Karjakin
||0-1||34||2019||Gashimov Memorial||C53 Giuoco Piano|
|7. Ding Liren vs Grischuk
||1-0||77||2019||Gashimov Memorial||D70 Neo-Grunfeld Defense|
|8. Topalov vs Navara
|| ||½-½||55||2019||Gashimov Memorial||B12 Caro-Kann Defense|
|9. Mamedyarov vs Radjabov
||½-½||41||2019||Gashimov Memorial||D02 Queen's Pawn Game|
|10. Carlsen vs Anand
||1-0||43||2019||Gashimov Memorial||D37 Queen's Gambit Declined|
|11. Grischuk vs A Giri
|| ||½-½||22||2019||Gashimov Memorial||D38 Queen's Gambit Declined, Ragozin Variation|
|12. Karjakin vs Topalov
|| ||½-½||32||2019||Gashimov Memorial||C53 Giuoco Piano|
|13. Radjabov vs Ding Liren
||½-½||43||2019||Gashimov Memorial||C89 Ruy Lopez, Marshall|
|14. Navara vs Carlsen
||0-1||58||2019||Gashimov Memorial||B33 Sicilian|
|15. Anand vs Mamedyarov
||1-0||63||2019||Gashimov Memorial||C50 Giuoco Piano|
|16. Mamedyarov vs Navara
||½-½||85||2019||Gashimov Memorial||D38 Queen's Gambit Declined, Ragozin Variation|
|17. Karjakin vs Grischuk
||½-½||32||2019||Gashimov Memorial||D73 Neo-Grunfeld, 5.Nf3|
|18. A Giri vs Radjabov
|| ||½-½||40||2019||Gashimov Memorial||D37 Queen's Gambit Declined|
|19. Ding Liren vs Anand
||½-½||34||2019||Gashimov Memorial||D37 Queen's Gambit Declined|
|20. Topalov vs Carlsen
||½-½||36||2019||Gashimov Memorial||D38 Queen's Gambit Declined, Ragozin Variation|
|21. Carlsen vs Mamedyarov
||½-½||37||2019||Gashimov Memorial||D32 Queen's Gambit Declined, Tarrasch|
|22. Navara vs Ding Liren
||1-0||45||2019||Gashimov Memorial||D49 Queen's Gambit Declined Semi-Slav, Meran|
|23. Anand vs A Giri
||1-0||39||2019||Gashimov Memorial||C65 Ruy Lopez, Berlin Defense|
|24. Radjabov vs Karjakin
|| ||½-½||41||2019||Gashimov Memorial||E06 Catalan, Closed, 5.Nf3|
|25. Grischuk vs Topalov
||1-0||69||2019||Gashimov Memorial||D37 Queen's Gambit Declined|
| page 1 of 2; games 1-25 of 45
< Earlier Kibitzing · PAGE 21 OF 21 ·
|Apr-16-19|| ||Sokrates: <ChessHigherCat: The worst part is you can never ask your wife! I usually have it narrowed down to the 8th or the 18th.> LOL. Just give us your wife's email-address, and <moronovich> and I shall ask her discretely!|
|Apr-16-19|| ||Sally Simpson: ***
Celebrating (perhaps not the correct word) our 42nd anniversary this year.
You may forget it once but believe me on this, you never will forget it again.
|Apr-16-19|| ||AylerKupp: <<Sokrates> LA? I thought you were situated in Cuba. >|
No, I was born in Cuba. But I came to the USA when I was 11 and my family moved to LA when I was 13. So I have been in LA for a long time.
|Apr-16-19|| ||AylerKupp: <<Pedro Fernandez> But my family and friends tell me that I'm a good barbecue.>|
People are different. In spite of my skills in the kitchen I have absolutely no talent for barbequing. My wife on the other hand, does. So she does all the barbequing in our family. A reversal of the usual stereotyping.
|Apr-16-19|| ||AylerKupp: <ChessHigherCat> If you have a problem remembering the day of your anniversary you might appreciate this true story:|
My wife and I were at a party long ago and someone asked us how long we had been married.
I miscounted and said "Eight years of wedded bliss."
My wife hit me on the ribs and said "We've been married nine years!"
In what was probably my best recovery ever I quickly said "I know we've been married nine years, but eight of wedded bliss." Phew!
So now every year on our anniversary she smiles and says "Well, at least our ratio is getting better."
|Apr-16-19|| ||AylerKupp: <Sally Simpson> I was at a wedding reception some years ago and the best man (the groom's brother) gave the toast and advised his brother that "If you want to make sure that you remember your wedding anniversary each year, just forget one of them." How true.|
Then again, our wedding anniversary is the day after Christmas, so it's hard to forget. But as a good omen I remember that it rained for a solid week (very rare in Los Angeles) before the day of our wedding. On our wedding day the weather cleared up and was bright, sunny, and cloudless all day. The day after our wedding it began to rain again and rained for another solid week.
So, to keep this post somewhat on-topic, planning the date for your wedding is like playing a chess combination, you need to be able to see many moves ahead.
|Apr-16-19|| ||Check It Out: <AylerKupp> your wedding weather was very similar to mine. I got married in Guam in August, the rainy season in the S Pacific, and sure enough, it had been raining heavily for days leading up to the wedding. I'm talking rain where you are soaked to the bone in a matter of seconds. But on the day of the wedding the clouds and rain broke and the sun came out for a beautiful 80 F day. The ceremony and reception were great. Later that day, it started to pour again. We were very happy with sky gods omen.|
|Apr-16-19|| ||Sokrates: Thanks for the info, <AylerKupp>. I can't tell exactly why, but it somehow didn't feel right that you were in Cuba.|
You don't happen to know a minor city called Gold Beach north of LA? An internet friend of mine is mayor there. Know him from a site about mechanical watches (a former but not gone passion of mine).
|Apr-16-19|| ||MrMelad: <Pedro Fernandez> I didn’t mean discussing those issues would be off topic anywhere on CG, my forum can be a good place for that. I don’t blame you if you aren’t interested though.|
In any case thanks again for your comments :)
|Apr-16-19|| ||ReneDescartes: @<Pedro Fernandez> The continuum hypothesis doesn't prove anything, and the reason is that it's not necessarily true! To certain standard axioms of arithmetic it could be added, but also its negation could be added, without producing a contradiction. You can't prove it or disprove it; you can merely decide to stipulate it or not if you wish. Many mathematicians do not wish to do so.|
The reason the rationals are denumerably infinite is a lot simpler than that. Each rational number except zero can be given a "height," for example the sum of the absolute values of the numerator and denominator; and the number of fractions with each height is finite. Using this, you can just list the nonzero reduced fractions in order--first those whose numerator and denominator add to a "height" of 2 (1/1 and -1/1), then to 3 (1/2 and 2/1 and their negatives), then to 4 (1/3,3/1, -1/3, -3/1), then to 5 (1/4, 2/3, 3/2, 4/1, etc.), and so on. Any infinite set where you can give to all the elements (or all but a finite number of them) such a height, and where no height belongs to infinitely many elements, is always countable--for you can construct a 1-1 correspondence between its elements and [1,2,3,...].
Pretty sure Frogbert likes rationals.
|Apr-16-19|| ||Gypsy: <ReneDescartes: .... The continuum hypothesis doesn't prove anything, and the reason is that it's not necessarily true! To certain standard axioms of arithmetic it could be added, but also its negation could be added, without producing a contradiction. You can't prove it or disprove it; you can merely decide to stipulate it or not if you wish. Many mathematicians do not wish to do so.>|
The continuum hypothesis is a hypothesis, not an axiom, right? All mathematicians I have ever talked to about this believe CH to be true, though the proof is elusive.
The situation is similar to that of the Riemann Hypothesis:
No proof, but also no counterexample. Yet it would be weird to claim Riemann Hypothesis to be an axiom and choose it to be false.
In contrast, the situation is different from that of the Axiom of Choice, for instance, which is believed to be a bona fide axiom. There you can chose for it not to hold and, by the way, a bunch of intuitively weird results in topology (associated with certain non-measurable sets) thus disappear.
|Apr-17-19|| ||ReneDescartes: No, the Riemann Hypothesis could be proved, as far as we know--it just hasn't been. It's like Fermat's Last Theorem was before Wiles. The continuum "hypothesis" is in a stranger case: it can neither be proved nor disproved--*that* has been proved.|
|Apr-17-19|| ||john barleycorn: of course, there was hope to prove the Continuum hypothesis, as well as there was hope to solve Fermat's last theorem. Just the solutions look different. Fermat was proven. The continuum hypothesis (in fact the consistency of it with ZFC set theory)was "solved" in an unexpected way, saying it does not matter as it is independent from the axioms of ZFC and either assumption of it (accept or refuse) does not lead to contradictions in ZFC if ZFC is free from contradictions. A whole different animal. Whether Riemann's hypothesis can be proven in the one or other way is an open question. It may turn out to be of the Fermat type or not.|
|Apr-17-19|| ||nok: As I see it the continuum hypothesis is a kind of Occam razor, saying some strange intermediate sets don't exist. I haven't seen any use for them anyway.|
|Apr-17-19|| ||john barleycorn: <nok> in fact, I think it classifies as a "pseudo problem" in Wittgenstein's (?) terminology.|
|Apr-18-19|| ||Sokrates: I wonder when the Grenke will appear on Chessgames. Only four days to go before the tournament begins. Here we are stuck with turkeys, razors, axioms, hypothesises and marriage anniversaries! :-)|
|Apr-18-19|| ||Gypsy: <The continuum "hypothesis" is in a stranger case: it can neither be proved nor disproved--*that* has been proved.>|
But the continuum "hypothesis" can certainly be disproved! It would suffice to show one instance of a set with cardinality between countable and continuum. What are we missing?
|Apr-18-19|| ||john barleycorn: <Gypsy: ... What are we missing?>|
|Apr-18-19|| ||Gypsy: <john barleycorn: <Gypsy: ... What are we missing?>|
Hmm, that is the hard direction of these conjectures/hypotheses -- the <"there is <no> instance such that ...."> direction.
It is the hard direction such as, to give another notorious example, this time from computational complexity field, in the P/NP conjecture. The hard direction is
P \not= NP
"... there is no polynomial time algorithm that solves NP hard problems".
The 'easy' direction of settling the 'P/NP conjecture' would be,
P = NP
where you could just present an algorithm that solves, say, integer linear programs (or 3SAT) in polynomial time O(n^k). Then the P/NP hypothesis would be settled. But since all 'smart money' really is on P \not= NP being true, we do not really expect to see such an example any time soon.
In the 'hard direction', there may be a proof and we just have not found it yet; or there may not even be a proof and we are running into an example of a Kurt Goedel type of result.
(Kurt Goedel paraphrased: Within any axiomatic system will exist easily stated true 'theorems' that do not have finite proofs.)
|Apr-18-19|| ||nok: <<<But the continuum "hypothesis" can certainly be disproved! (...) What are we missing?> The counterexample?> |
Hmm, that is the hard direction>
Not just hard, you need a new axiom for that. But what's the point?
|Apr-18-19|| ||john barleycorn: The findings of Gödel and Cohen showed that the continuum hypothesis is independent of ZFC and thus whether it is right or wrong it is of no importance to the foundation of mathematics. In ZFC and IF (thats the important part) ZFC is free of contradictions. In that way Gödel's later results showed there is no guarantee for that. You may have "true" theorems that be formulated in a formal language like ZFC but cannot be proven in there. That killed Hilbert's "Formalism" as a basis for mathematics.|
|Apr-19-19|| ||Sokrates: Grenke commencing within 24 hours.
Chessgames in deep coma. Knock-knock!
As much as the learned and erudite mathematicians have the undivided admiration of my ignorance, I am a bit more anxious to experience the strong Grenke tournament, in particular, of course, to see how the world champion will fare with Caruana, MVL and Aronian on the battle field.
|Apr-19-19|| ||keypusher: <Sokrates> There is a page open, though they have the start date wrong.|
Grenke Chess Classic (2019)
|Apr-19-19|| ||parmetd: The date seems right...|
|Apr-20-19|| ||Sokrates: Many thanks, <keypusher>, now I've got it. |
Still, it should be announced on the usual proper spot on the front page - it should not be hidden away like that.
Launching super tournaments in due time and easy to find - what can be more important for this site? I respectfully ask.
< Earlier Kibitzing · PAGE 21 OF 21 ·
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