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beatgiant
Member since Jun-05-04 · Last seen Sep-03-15
An American amateur.

Following are positions on many hot-button issues of the site.

Greatest player of all the 18th century? Philidor.

Who would have won a hypothetical Staunton-Steinitz matchup? Steinitz.

Was there an unwritten "win by two" clause in the Lasker-Janowski (1910) match? No.

Did Alekhine deliberately throw the 1935 title match, so as to get a rematch and thus be paid twice for playing Euwe? Hmmm....

Did Stalin order Flohr not to try hard to beat Botvinnik? No.

Who would have won a never-played Fischer-Gligoric match? Fischer.

What's the worst opening? 1. h4.

>> Click here to see beatgiant's game collections.

   beatgiant has kibitzed 2143 times to chessgames   [more...]
   Aug-28-15 Carlsen vs W So, 2015 (replies)
 
beatgiant: <Pulo y Gata> 33...Rxc4 34. Rxc4 and then what? Then the immediate 34...d5 35. Rxd5 does not work.
 
   Aug-16-15 H Koch vs R Dahlstrom, 2007 (replies)
 
beatgiant: <JimFromProvidence> After 38. Rh8, why can't Black play a king move like 38...Ke5 or 38...Kg6? Can you post an actual line?
 
   Aug-09-15 Reshevsky vs Feuerstein, 1957 (replies)
 
beatgiant: <fallen angel> 26...Kg8 27. Re8+ Rxe8 28. Rxe8+ forces Black to release the pin on the bishop, and wins Black's queen.
 
   Aug-04-15 Kupreichik vs Tal, 1970 (replies)
 
beatgiant: <al wazir> 30. Be6 Bxe6 31. Rxe6 <Bg5> blocks the threats and attacks White's queen. White might still win, but it doesn't look as simple as the game line.
 
   Jul-30-15 Kasparov vs Anand, 1998 (replies)
 
beatgiant: <tivrfoa> White has Nd6+.
 
   Jul-28-15 Fischer vs Petrosian, 1962
 
beatgiant: <RookFile> Was anyone actually claiming a clear Black win? I do think Black would keep a noticeable advantage after something like 36. h3 e5 37. Kf2 Nh7 38. Rc2 Ng5, but of course it often took a lot more than that to beat Robert J. Fischer.
 
   Jul-24-15 Louis F Stumpers (replies)
 
beatgiant: Given ab - c = (power of 2) and ac - b = (power of 2), adding the two equations gives ab + ac - (b + c) = power of 2 plus other power of 2 and factorizations are possible. ab + ac - (b + c) = (a - 1)(b + c) and 2^i + 2^j = 2^i[1 + 2^(j-i)] and that could help when proving ...
 
   Jul-23-15 Karpov - Fischer World Championship Match (1975) (replies)
 
beatgiant: <AylerKupp> I'm still not sure what <win by 2> means without a tied match provision. Suppose the match is for first to get 10 wins, and the match reaches 9-9. Does the required number of wins now become 11? and if the match then reaches 10-10 does the required number
 
   Jul-19-15 Kasparov vs Gligoric, 1983 (replies)
 
beatgiant: <tivrfoa> 19...Bxe5 20. dxe5 Qxe5 21. b4 Nc4 22. Rxc4 dxc4 23. Qxd8.
 
   Jul-15-15 Euwe vs C Vlagsma, 1940 (replies)
 
beatgiant: <leow> When Black plays ...g5, White can always reply with f5 and I don't see how either side can break through. 40...g5 41. f5+ Ke5 42. Kh5 Kf6 43. Kg4 Ke5 etc.
 
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