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petrie911
Member since Mar-10-09
no bio

   petrie911 has kibitzed 19 times to chessgames   [more...]
   Jul-08-14 Kamsky vs L Dominguez, 2013 (replies)
 
petrie911: <gawain>: Black can't play 45 ... Rh3+ because he is in check, making it an illegal move.
 
   Apr-14-14 L Josteinsson vs Petursson, 1984 (replies)
 
petrie911: He probably calculated the forced mate in 3 and just played it. Once you have a guaranteed win, there's no reason to try to make it faster.
 
   Mar-24-14 D G Baird vs Albin, 1894 (replies)
 
petrie911: Took me about 30 seconds to get. Mostly because I read it as "22. ?".
 
   Dec-15-10 Guimard vs Najdorf, 1948 (replies)
 
petrie911: I got to 43...Bh2+, but somehow missed the mate. Instead, I found 44...Bf4+, picking up the queen. Black has a queen and 3 pawns for two bishops, which I believe is a crushing advantage.
 
   Dec-11-10 R Fontaine vs NN, 2001 (replies)
 
petrie911: As noted, 8.Qd6+ forces mate. Perhaps would have made for a good puzzle.
 
   Oct-19-10 N Vlassov vs A Iljushin, 2003 (replies)
 
petrie911: Seeing as 43...Kc8 and 43...Kd7 are both total losses, what about 43...Kd6? Seems like black should be able to hold.
 
   Sep-27-10 A Burns vs Blackburne, 1885 (replies)
 
petrie911: Maybe I'm missing something, but it seems like 35...Nxe4 accomplishes the same thing. White's best reply seems to be 36. Rxh5 gxh5 and he's still down a Rook.
 
   Sep-16-10 Larry Evans vs Larsen, 1957 (replies)
 
petrie911: Rxf1 loses immediately to Qc5+. So, by process of elimination, Kxf1 is the correct move. ...seems like an odd puzzle.
 
   Jul-06-10 Julio Bolbochan vs A Rocha, 1966 (replies)
 
petrie911: 29. Qb2 (or 29. Qc3) does allow 29... Rf6, but it looks like 30. Bxb7 leaves Black in a tough spot (eg, 30...Nxb7 31. Nd5). Not an instant mate, but not pleasant for Black by any means.
 
   Oct-30-09 J Klavins vs Tal, 1954 (replies)
 
petrie911: <sfm: <As a compromise, keyboards are tuned just a bit off, so that all twelve keys sound pretty good. Hence, "well-tempered"> Actually tuned so the quotient of the frequency between any two subsequent half-notes has a ratio equal to the 12th root of 2 - but Bach would ...
 
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