|
< Earlier Kibitzing · PAGE 3 OF 3 ·
Later Kibitzing> |
| Sep-26-13 | | framsey: I will add that white plays a pretty miserable game here. Just look at the position after 18...cxb4! |
|
Sep-26-13
 | | patzer2: <bubuli55: 2 day><2 ways 2 go>
That's my thought. Either 28...Qc1 or 28...Qxd4 must be the solution to today's Thursday puzzle. Since 28...Qc1 is busted by 29. Bxb2!,
the solution has to be 28...Qxd4!
Calculating 28...Qxd4! to the final game position is a fairly quick exercise. Then after a little deeper look (e.g. 31...a3 32. Rd1 g6  ), it's clear one of the connected passers will promote and win. P.S.: Interestingly, 28...Qc1?? wins if White misses 29. Bxb2!  . |
|
Sep-26-13
| | patzer2: <framsey: I will add that white plays a pretty miserable game here. Just look at the position after 18...cxb4!> Seems to me White's problems begin early in the game. Instead of 6. e3 = to  , I think the more popular 6. e4!  is the better option. It avoids the buildup of the Black Queenside pawn majority which cause White's difficulties here. In the Opening Explorer, 6. e3 was played 19 times with 26% White wins and 47% Black wins, while 6. e4 was played 843 times with 41% White wins and 29% Black wins. Maybe White was trying to get Black into unfamiliar territory, but it obviously didn't help in this game. |
|
| Sep-26-13 | | eblunt: <morfishine: If <28.Rd4 Qxe3>> 28 Rd4 Qxd4 29 Bxd4 Rc1+ even easier. |
|
| Sep-26-13 | | Shamot: <framsey> "a rook can't stop two pawns on the 6th rank". It should be "a rook can't stop two CONNECTED pawns on the 6th rank". |
|
| Sep-26-13 | | LIzzard: for white, does
28 Kf1
save the game? |
|
Sep-26-13
| | anthro: Must be easy because I got it... |
|
| Sep-26-13 | | Shamot: <LIzzard: for white, does 28.Kf1 save the game?> 28.Kf1 is replied by 28...a3 and white has no saving move. |
|
Sep-26-13
 | | kevin86: This one is easy,but for the complication of back row mate threats at both ends of the board. The two pawns will beat the rook.
Here is a maxim:two far advanced connected pawns can beat a rook while two disconnected advance pawns will hold a rook. |
|
Sep-26-13
 | | perfidious: <anthro: Must be easy because I got it...> There are days when this feeling is only too familiar. |
|
Sep-26-13
 | | Domdaniel: Easy, really: the point being that Black needs the a-pawn to win. |
|
Sep-26-13
 | | Jimfromprovidence: It's the connected passed pawns plus no escape square for the king that makes this a winning position. This is the text winning position after 28 Bd4.
click for larger view The same position with the h pawn on h3 is losing for black.
click for larger viewBlack also faces the threat of a back rank mate. |
|
| Sep-26-13 | | dark.horse: Lesson here is in recognizing the power of advanced connected passers against a rook. The tactics are easy (for a Thursday) once one sees the plan. |
|
Sep-26-13
 | | Fusilli: <Jim from Providence> Yes, and this one:
click for larger view... is winning for black again. :) |
|
Sep-26-13
| | Fusilli: <morfishine: If <28.Rd4 Qxe3> The same theme emerges after 29.fxe3 Rc1+ 30.Rd1 Rxb1 31.Rxb1 a3 > Hm.. but 30.Kf2 and white wins. The threat of back rank mate does black in. <eblunt> is right, though, that simply 28... Qxd4 wins. |
|
Sep-26-13
 | | Penguincw: I was thinking of 28...Qc1, but the queen is protected, and Thursday puzzles can't be this easy. |
|
| Sep-26-13 | | bachbeet: Got it so it must be one of the easiest Thur puzzles. |
|
| Sep-26-13 | | pericles of athens: I think Laszlo will win. |
|
| Sep-26-13 | | peristilo: Can a good person translate that dude up there, "chrisowen", please? Or at least tell me what is his comment about? |
|
Sep-26-13
 | | OhioChessFan: <peristilo> The best way to enjoy an artist is not to dissect him- Philip W Sergeant |
|
Sep-26-13
 | | Check It Out: <Fusilli> <Jim from Providence> Good points about the king escape squares being critical to this puzzle. |
|
| Sep-26-13 | | morfishine: <Fusilli> I sure rushed that one! ***** |
|
| Sep-26-13 | | SamAtoms1980: First thought is 28....Qc1 but that doesn't look like it goes anywhere (it probably just loses the pawn). Then we see that the White rook has too much protecting to do: 28....Qxd4 goes two passed pawns up. After 29.Rxd4 Rc1+, does 30.Rd1 defend? Nope: 30....Rxb1 31.Rxb1 a3 wins. |
|
| Sep-26-13 | | Patriot: At first I thought 28...Qc1 was the answer. However the refutation would be 29.Bxb2. Then I considered 28...Qxd4:
29.Rxd4 Rc1+ 30.Rd1 Rxb1 31.Rxb1 a3 32.Kf1 a2 |
|
| Oct-21-20 | | RoseMei: Somebody should submit this as "game of the day", with the pun having something to do with the Nirvana song "Sappy". I would do it myself, but I can't think of anything clever right now. |
|
 |
|
|
< Earlier Kibitzing · PAGE 3 OF 3 ·
Later Kibitzing> |
Kibitzing
sac: 19...Rc8