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Eugenio Maciel German vs Washington de Oliveira
BRA-ch (1951), Fortaleza BRA, rd 9, Jul-??
Sicilian Defense: Najdorf. Amsterdam Variation (B93)  ·  1-0



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Kibitzer's Corner
Aug-09-17  clement41: 21 Rxg4 is also a candidate (as is 21 Rxe5), but I can't help thinking white thought he'd win material and perhaps even the queen with the zwichenzug 21 Rc4 enticing 21...Qxd5 in view of 22 Rxg4 opening the b1-h7 diagonal fxg4 23 Bxh7+ Kxh7 24 Qxd5. Yes, in this line white does win the queen.
But 24...Rf1# is a rude awakening.
And playing 22 Rxg4 fxg4 23 Rxf8+ doesn't help, as both 23...Rxf8 and 23...Kxf8 respectively reload the mate threat and remove the discovered check.

Another tactical idea is profiting from the alignment between Qd5/Kg8 with 22 Rxg4 fxg4 23 Bc4 but it's actually black who wins here too: either 23...Rf1+ 24 Bxf1 Qxd2 -+ and 23...Qxc4! 24 Rxf8+ Rxf8 25 h3 g3! -+ win for black. (22 Rxg4 fxg4 23 Rxf8+ doesn't make the combination work due to 23...Rxf8 renewing the mating threat).

Hence 22 Re1, getting the rook away from the vis--vis with the f8 rook and making all these threats real.

22...e4? is the decisive, tactical mistake, enabling 23 Rcxe4! that both attacks the Be7 and evacuates c4 for the bishop.

Jan-07-18  Triebe: 22.Tg4 wins the bishop.
Premium Chessgames Member
  FSR: <Triebe> As <clement41> explained, 22.Rxg4? allows simply 22...fxg4. Then 23.Rxf8+ Rxf8 (23...Kxf8 is also possible, removing the king from the light square) and now 24.Bxh7+? Kxh7 25.Qxd5 Rf1# or 24.Bc4? Qxc4 (24...Rf1+ 25.Bxf1 Qxd2 also wins) 25.bxc4 Rf1#.

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