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May-22-14
 | | doubledrooks: 50...Rf1 puts the question to the white queen, and there is no satisfactory answer. For example: a. 51. Qh4 Rh1+ 52. Kg3 Qe1+ 53. Rf2 Rf1 54. Kf3 Qe4+ 55. Kg3 Qe3+ 56. Rf3 Qe1+  b. 51. Qd4 h4 52. g3 Rh1+ 53. Kg2 Qf1# |
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| May-22-14 | | Kwesi: <nalinw> Black wouldn't be able to avoid perpetual check from the white queen (by playing ...Kh7) as described in <Once>'s post. |
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| May-22-14 | | howlwolf: Sometimes I leap before I look; I am at work so I don't spend much time solving. I went with an immediate 50 h4 seeing that 51 Qh4 Rh1+ 52 Kg3 Qe1+ 53Kg4 Qd2 pockets the rook, not realizing that white then has a perpetual. If Black presses for a win with 53...f5+ 54Kg5 Qd2 55Qh6+ Kg8 56Kf6 looks like it mates. Not a good way to start the day! |
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May-22-14
 | | Jimfromprovidence: <offramp> <50.b5 may be a mistake but what is the improvement?> 50 Kg3 seems much better, but those 2 b pawns don't seem that safe. 
click for larger view |
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May-22-14
| | Jimfromprovidence: Note the 3-fold repetition after 36 Qf2.
click for larger view |
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| May-22-14 | | PJs Studio: This isn't a particularly difficult puzzle but I got it wrong even though I considered only ...Rh1, ...Rf1, ...h4, and combinations of Rh1 FIRST! "Patzer sees check, gives check." There was a book (released in the US years ago) that was entitled "The Heavy Pieces in Action". When I read the title as a teenager I thought "...Ohhh! I play the heavy pieces like a orangutan recovering from an aneurism. Must. Buy. Book." Needless to say, I never got the book...and never recovered from the aneurism either. |
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May-22-14
| | ajk68: <Omnias: ajk68: In your line after 54. Qf6+ Kh6 there is 55. Qh8#>
<Omnias: Correct is 51.Qh4 Rh1+ 52. Kg3 Qe1+ 53. Rf2 Rf1 54. Qf6+ Kg8 55. Qd8+ Kh7> Good catch. You are correct on both accounts. |
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| May-22-14 | | Rookiepawn: Aaaaaggghhhh! I was on the right track, following a train of thought similar to that of <Once> (I found your explanations wonderful, btw) but... ...for some strange reason my primitive brain discarded the correct line because it wrongly assumed that 54.Qf6+ leads to perpetual! Never thought of simple nice 55 ... Kh7! So I say to myself: there are some automatic assumptions that need to be challenged when calculating variants. Don't be sure about that sure thing. Be water my friend. Think twice, you nitwit! |
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| May-22-14 | | Dr. J: None of the posts so far is fully adequate to refute 51 Qh4. There follows: 51...Rh1+, 52 Kg3 Qe1+, 53 Rf2 Rf1.
Now many posters have elegantly refuted 54 Kf3, but the critical line continues: 54 Qf6+ Kg8, 55 Qd8+ Kh7, 56 Qb6 
click for larger viewHere <Once> gives 56...h4+, but that is insufficient against 57 Kf3 Qe4+ 58 Kg4. Right back at the beginning of the discussion <hcgflynn> said: <56. - g5! wins> but provided no analysis. His idea, presumably, is then 57 fg?? h4+ 58 Kf3 Qe4#. But matters are still not completely settled. For instance: 56...g5, 57 Qd4 (Is this best?) h4+, 58 Kf3 Rxf2+, 59 Qxf2 Qe4+, 60 Kg4 Qf5+, 61 Kf3 Qxf4+, 62 Ke2 Qxe5+. 
click for larger viewNow I presume Black is winning, but White can still fight. Comments? Improvements, please? |
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| May-22-14 | | sombreronegro: I thought 50 ... Rf1 was a good move. Looked easier until I saw the queen stopping h4. h4 was my 5 second idea. Rf1 is non committal and the white queen does not seem to have a better place than on the e1-h4 diagonal to stop h4. g3 is mate and h4 loses the rook. The only other interesting line seemed to be Rh1+ check immediately .Looked into the walk the plank idea but sacking pawns guarding your own king seem like a bad idea. Knowing how it would turn out is one thing, but I think harassing the queen would be a popular move. |
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May-22-14
 | | kevin86: Black had to chase the queen from h4, and the put the pawn there to wall in white- like a can of mixed nuts...lol |
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| May-22-14 | | sombreronegro: yeah, 3.e5 allows black to transpose into an easy French defense without the problem bishop. 5. Be2 and black has already equalized. White's white square bishop is never better than black's and when it moves to a more aggressive square its swapped off. A French defense player's dream I think... |
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| May-22-14 | | Madman99X: Dr. J, in your diagram:
click for larger view 56... h4+ 57. Kf3 is answered by ...Qd1+ and the white king is caught up in a mating net. 58. Ke3 Re1+ 59. Re2 Qxe2+ 60. Kd4 Qe3# (Houdini finds this stuff much quicker than I do.) I did not solve the puzzle, unfortunately. I kept trying to make the immediate 50... h4 work, and it just plain doesn't. |
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| May-22-14 | | Dr. J: <Madman99X> You are right, of course. Credit to <Once> for the win. |
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May-22-14
 | | chrisowen: Ogle a f1 rook empirical back slide cuffed and b1
ruled the roost miffed meddle pawn b5 allows the rook to keep abreast of whites lust again to gain b5, evermore a queen at the back-drop of defending along a second rank light finally cracks to the pressure of being facetious maybe hoping to get away b5 out of the darkness a dock b5 reticence
rook first deflects a f2 queen band quest vip
treat-ment-in-story am got a king bottle necked at a h2 given the royal up and under play too deed rook catch a whiff one spot in family picnic heading over now a g3 king every chace to escape before at g3 sugar field of dreams pawn b5 on us ok this time at hatchet etc to berth bounce a pawn b5, looks happy to set sail in ja bind queen backs up holy free frets again slide a b1 often alley oop in accolade an umbrella term one crown fetch a live in kings wire bus at have on age forfeit her bind in head a f2 why duck the issue king needed to escape the clutch drive of rook chain gang h1 or deem in a tour hone in king a h2 headed for try to fly as effect a be be gun pointed at his head et tu brute if ive got this correct back be word on the street corner ok a rook enough in district band to moaner borough smiles wiped off lights face b5 one to pick a f2 aint half er by bad just reticence on gauge i shall demon-strate a feel first a king needs to seek high ground catch a wave in torment pawn b5 need bind as no good re i would pray for at g3, really best bonus to stipulate a king up ply in black sets the sails all bound better for too high seas a jag ship a ground dutiful crum only heavy pieces as food for thought delivery rook dead churlish a pet behaviour off form re a having ado done liege network in free to bet pawn immaterial black has big fish to fry a request put in afford damage done b5 up and headed for the light whilst a king het up and no place to go so honour a cramping f1 first if the truth be known shunt queen each king left to his own devices right reap queen bag a tell b5 do the math add in some queen undercoat better mc factor delve grip it now in judged jod h4 erm hopper strike a note a boom in f1. |
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| May-22-14 | | BOSTER: I like how <Madman99X> precisely translates <Once': 56...h4+ 57.Kf3 Qe4+ and the walls come tumbling down>
like <56...h4+ 57.Kf3 Qd1+!>. |
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May-22-14
 | | gawain: Nicely done. Black will win if his pawn in on h4, but he does not win with the immediate 50...h4 because of 51 g3. So 50...Rf1 forces the queen to depart the f2 square and renders g3 inadequate as a defense against the ensuing ...h4. Simple, really, but sweet. |
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| May-22-14 | | patzer2: <Madman99X><I did not solve the puzzle, unfortunately. I kept trying to make the immediate 50... h4 work, and it just plain doesn't.> I also tried without success to make 51...h4 work. However, it comes oh so very close to the winning line. After 51...h4? 51. Qxh4 Rh1+ 52. Kg3 Qe1+ 53. Rf2 Rf1 54. Qf6+ Kg8 55. Qd8+ Kh7 we get the position (below) 
click for larger viewwhen 56. Qh4+ gives White has a draw by perpetual check (e.g. 56. Qh4+ Kg7 57. Qf6+ Kg8 58. Qd8+ Kh7 59. Qh4+ Kg8 60. Qd8+ =). After 51...Rf1! 51. Qh4 Rh1+ 52. Kg3 Qe1+ 53. Rf2 Rf1 54. Qf6+ Kg8 55. Qd8+ Kh7 we get almost the identical position (below), 
click for larger viewexcept the pawn on h5 is no longer missing and that makes the draw by perpetual with 56. Qh4+ = no longer available. As noted by you and <Once>, in the position just above, the last ditch attempt to hold with 56. Qb6 fails to 56...h4+ 57. Kf3 Qd1+! 58. Ke3 Re1+ 59. Re2 Qxe2+ 60. Kd4 Qe3#. |
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| May-22-14 | | YouRang: <Jimfromprovidence: Note the 3-fold repetition after 36 Qf2.> Hmmm, I see that the board is set up the same way in these three cases: (1) After 30...Qe4
(2) After 32...Qe4
(3) After 36.Qf2
But the first two cases it is white to move; in the third case it's black to move. In order to count as 3-fold repetition, doesn't it have to be the same side to move each time? |
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| May-22-14 | | trnbg: There are striking similarities between this game and Nimzowitsch vs. Capablanca, New York 1927: The opening (Caro Kann advance Variation), Black's strategy and Invasion of the White Position via the C-file, and the finish with Queen and Rook... |
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| May-22-14 | | Whitehat1963: I actually got this one! Another Thurday solved! Yay! |
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May-22-14
| | Jimfromprovidence: <YouRang> <Hmmm, I see that the board is set up the same way in these three cases: (1) After 30...Qe4
(2) After 32...Qe4
(3) After 36.Qf2
But the first two cases it is white to move; in the third case it's black to move. In order to count as 3-fold repetition, doesn't it have to be the same side to move each time?> This is the relevant rule from FIDE, Article 9.2
"The game is drawn upon a correct claim by the player having the move, when the same position, for at least the third time (not necessarily by a repetition of moves):
a. is about to appear, if he first writes his move on his scoresheet and declares to the arbiter his intention to make this move, or
b. has just appeared, and the player claiming the draw has the move. Positions as in (a) and (b) are considered the same, if the same player has the move, pieces of the same kind and colour occupy the same squares, and the possible moves of all the pieces of both players are the same. Positions are not the same if a pawn that could have been captured en passant can no longer be captured in this manner. When a king or a rook is forced to move, it will lose its castling rights, if any, only after it is moved". Section b. seems to indicate that the same player does not have to have the move each of the three times. But since black did not declare it it's a moot point in this case I guess. |
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| May-22-14 | | YouRang: <Jimfromprovidence> Thanks for posting the rule. However, within part (b), it says this: <Positions as in (a) and (b) are considered the same, if the <<<same player has the move>>>, pieces of the same kind and colour occupy the same squares, and the possible moves of all the pieces of both players are the same.> For amusement: In the Wikipedia article on 3-fold repetition, it gives the following example of an *incorrect claim* of this rule: <Fischer vs. Spassky, 1972
In the twentieth game of the Bobby Fischer versus Boris Spassky World Chess Championship 1972, Fischer called the arbiter Lothar Schmid to claim a draw because of threefold repetition. Spassky did not dispute it and signed the scoresheets before the arbiter ruled (Gligorić 1972:119). After the draw had been agreed, it was pointed out that the position had occurred after White's forty-eighth and fiftieth moves, and again after Black's fifty-fourth move (the final position). So the claim was actually invalid because it was not the same player's turn to move in all three instances, but the draw result stood.> |
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| May-22-14 | | BOSTER: In this flat triangle : rook d2-queen f2-king h2
Cherchez la Femme. |
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| May-22-14 | | TheBish: T Petenyi vs Bacrot, 2014 Black to play (50...?) "Medium", White is up a pawn.
My first candidate move was 50...h4, which would win after 51. Qxh4 Rh1+ 52. Kg3 Qe1+ 53. Rf2 Rf1 54. Kf3 Qe4+ 55. Kg3 Qe3+ 56. Rf3 Rxf3+ 57. gxf3 Qg1#. However, White should not take the pawn but play 51. g3! and White is fine, perhaps winning. The key is to drive White's queen away before playing ...h4. 50...Rf1 and now:
(A) 51. Qh4 would lose as in the variation above: 51...Rh1+ 52. Kg3 Qe1+ 53. Rf2 Rf1 54. Kf3 Qe4+ 55. Kg3 Qe3+ 56. Rf3 Rxf3+ 57. gxf3 Qg1#. (B) 51. Qe3 h4 52. g3 Rh1+ 53. Kg2 Qf1#.
(C) 51. Qe2 h4 52. g3 Rh1+ 53. Kg2 Qg1+ 54. Kf3 Qxg3#. |
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