Oct-19-18 A Sokolsky vs Pachman, 1947 
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steinitzgambit: The endgame would run as follows: 73. Kd4 Nxf4 74. Nh1 Ng2 75. Ng3 Nxh4 76. Ke3 c5 77. Ne2 c4 78. Nf4 c3 79. Ne2 Kb2 80. Kf2 c2 81. Kg3 f4+ 82. Nxf4 Nf5+ 83. Kf3 c1=Q 84. Nd3+ Kb1 85. Nxc1 Kxc1 86. Ke2 Nd4+ 87. Ke3 Ne6 88. Ke4 Nxg5+ 89. Kf4 Nf7 90. Ke3 h4 0-1 FEN: [DIAGRAM] |
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May-05-18 Rubinstein vs E Cohn, 1911
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steinitzgambit: The situation is not so clear if Black plays 37...Rf8! instead of 37...Rb2? Then Cohn could possibly have achieved a draw with: 38.h5 Rf7 39.Rf1 Rxf1+ 40.Kxf1 Kf7 41.Kg2 Kg7 42.Kg3 h6 43.Kf4 Kh7 44.g6+ Kg7 45.Kg3 Bc8 46.Kh4 Bd7 47.Be2 Kg8 48.Kg3 Kh8 49.Kf4 Kg7 50.Bg4 Bc8 ... |
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May-01-18 Levenfish vs P Johner, 1911
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steinitzgambit: In the position after Black played 53...Rxa5 White continued with 54. Rh5. Playing instead 54.c3 would also result in a draw: 54.c3 Ra4 55.Kd3 Rh4 56.Rg8 Rh3+ 57.Kd2 Kb6 58.Rb8+ Kc7 59.Ra8 Rh6 60.Kc2 c5 61.Rf8 Kc6 62.Rf5 Rh2+ 63.Kd1 Rh1+ 64.Kc2 Rh3 65.Rg5 Rh2+ 66.Kc1 Rh6 ... |
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Apr-30-18 H C Plunkett vs Steinitz, 1875
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steinitzgambit: I would like to endorse Honza Cervenka's analysis. Steinitz could have won with 25...Qa6! instead of 25...Qa5? Then the game would have run as follows: 25. Ke2 Qa6 26. c3 Bf8 27. Ng5+ Kg8 28. Qd5+ Be6 29. Nxe6 Qxe6 30. Qxe6+ Rxe6 31. Kf3 Bd6 32. d4 Kf7 33. f5 Rxe5 34. dxe5 ... |
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Apr-29-18 G Thomas vs Yates, 1925
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steinitzgambit: Instead of giving up the c-pawn in the 22nd move by ...Raf8, Black could have played 22. ..Qc7! A possible continuation would be: 22.Bf4 Qc7 23. Re1 Raf8 24. Bxe5 Rxe5 25. Rxe5 Bxe5 26. f4 Bf6 27. Qd5+ cxd5 28. Rxc7 Bd4+ 29. Kg2 Re8 30. Kf3 Re3+ 31. Kg4 Re2 32. Rd7 Rxa2 33. ... |
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Oct-07-17 S Rosenthal vs Winawer, 1867
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steinitzgambit: The endgame sequel is:
46. b8=Q+ Kc2 47. Qh2+ Kb1 48. Qh1+ Ka2 49. Qxa1+ Kxa1 50. Nb7 Kb1 51. Nd6 h6 52. gxh6 gxh6 53. Ke5 Kc1 54. Kf6 Kd2 55. Nxf7 Bxf7 56. Kxf7 Ke3 57. Kg6 Ke4 58. Kxh6 Kf5 59. h5 Kf6 60. Kh7 Kf7 61. h6 Kf8 62. Kg6 Kg8 63. Kf6 Kh8 64. Kg5 Kh7 65. Kh5 Kh8 ... |
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