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The World vs Gert Timmerman
C U R R E N T P O S I T I O N

Can a group of chess amateurs team up to beat a grandmaster? Find out in the Chessgames Challenge! You can vote for the move you think is best, and discuss the game with other members on this page.

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[G.J. Timmerman]

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GAME OVER: 1-0

[flip board]

MOVES:
1.d4 f5 2.g3 Nf6 3.Bg2 g6 4.c4 Bg7 5.Nc3 O-O 6.Nf3 d6 7.O-O c6 8.Qb3 Na6 9.Rd1 Kh8 10.Qa3 Nc7 11.d5 Bd7 12.Rb1 a5 13.dxc6 bxc6 14.c5 Ne4 15.cxd6 exd6 16.Bf4 d5 17.Be5 Re8 18.Bxg7+ Kxg7 19.Rbc1 Qe7 20.Qxe7+ Rxe7 21.Na4 Nb5 22.Nb6 Ra6 23.Nxd7 Rxd7 24.Ne5 Rd6 25.f3 Nf6 26.a4 Nc7 27.Bf1 Re6 28.f4 Ne4 29.e3 Rb6 30.Bd3 Na6 31.b4 Nxb4 32.Bxe4 fxe4 33.Nd7 Rb7 34.Nc5 Ree7 35.Nxb7 Rxb7 36.g4 Rc7 37.Rc5 Ra7 38.h4 Ra6 39.Rcc1 Kf6 40.Rf1 Nd3 41.Rb1 h5 42.gxh5 gxh5 43.Rb8 c5 44.Rfb1 d4 45.Kf1 dxe3 46.Rf8+ Ke7 47.Rbb8 Rg6 48.Rbe8+ Kd6 49.Rxe4 Kd5 50.f5 Rg3 51.Rfe8 c4 52.f6 Rf3+ 53.Ke2 Rxf6 54.Kxe3 Rc6 55.Rd4+ Kc5 56.Rb8 Re6+ 57.Re4 Rxe4+ 58.Kxe4 Nf2+ 59.Kf3 Ng4 60.Rb5+ Kd4 61.Rxh5 c3 62.Ke2 1-0
GAME OVER thank you for playing	it is now 18:37:45
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< Earlier Kibitzing · PAGE 1396 OF 1784 · Later Kibitzing>
Apr-08-08		krpvksprv: GMT is forced again to use his weeklong extension. This game has become like the TV show, "Who wants to be a Millionaire" where the contestant has 2 or 3 lifelines to use when he is in doubt. This is hopefully his final extension. White looks good thus far.

Apr-08-08		krpvksprv: <<Tabanus> Nothing will render ignoscible our conduct in here. GMT will vellicate our noses if he thinks that any chess diarthrosis thereby could be performed - if he thinks he should not impignorate his reputation.> Awesome wordings, eh...what does this mean again? LOL! Xp

Apr-08-08		DarthStapler: I have a question, is Timmerman using computer assistance in this game?

Apr-08-08		edda zeitz: <belgradegambit: The answer is 42.> Isn't this the answer to every question!

Apr-08-08		truefriends: < DarthStapler: I have a question, is Timmerman using computer assistance in this game? > Yes, http://www.chessgames.com/perl/cond...

Apr-08-08		edda zeitz: <krpvksprv: Awesome wordings, eh...what does this mean again?> Norwegian Newspeak, C vocabulary.

Apr-08-08		rinus: <Blablanus>

Apr-08-08		Lambda: <0^0 is indeterminate form, it just can't exist> Actually, 0^0=1. For any two cardinals K,L, K^L is defined as the cardinality of the set of functions from L to K. 0 is the cardinality of the empty set, so 0^0 is the cardinality of the set of functions from the empty set to the empty set. And there is precisely one such function, namely the empty set. So 0^0=1. The most meaningful way to show that 0.99999recurring and 1 are decimal representations of the same number is to observe something like the fact that the sequence 0.9, 0.99, 0.999 ... converges to both of them, thus the same definition can result in both of them. (Depending on which of the many possible ways you use to define the reals.)

Apr-08-08		ajile: <jovack: Thanks <ajile> for the advice!> You could also chase the bishop with Nh5. :o)

Apr-08-08		ajile: You math guys here's a hot debate topic that I saw argued for a week on another forum. Can .99999~ (9's to infinity) ever equal 1? :o)

Apr-08-08		YouRang: <ajile> 0.9999... is exactly equal to 1.0 :-)

Apr-08-08		monopole2313: For an interesting arithmetic lesson, check out http://www.youtube.com/watch?v=Bfq5...

Apr-08-08		jepflast: This should be proof enough for most: 1/9 = 0.111... 2/9 = 0.222... 3/9 = 0.333... ... 9/9 = 0.999...

Apr-08-08		Dr. Funkenstein: For slightly larger values of .9 (recurring) it will equal 1 :-)

Apr-08-08		YouRang: If <jepflast>'s proof doesn't convince you, consider this: [1] let x = 0.9999... [2] Multiply both sides by 10: 10x = 9.9999... [3] Subtract 9 from both sides: 10x-9 = 0.9999... [4] Substitute (using [1]): 10x-9 = x [5] Solve for x: 10x-x = 9 -> 9x = 9 Thus, x = 1 Q.E.D.

Apr-08-08		rinus: <YouRang> didn't change from Cantor's bike.

Apr-08-08		Nightranger: < edda zeitz: <belgradegambit: The answer is 42.> Isn't this the answer to every question! > Well, that or 'C'. < ajile ... You could also chase the bishop with Nh5. > How does this help the factorial thing? < monopole2313 > Good video. < jepflast & YouRang > Where is the "Women are Evil" proof? :-)

Apr-08-08		Tabanus: Bla bla bla ... Check out this chess gallery: http://eu.art.com/asp/display-asp/_... and these players http://www.epilogue.net/users/puimu...

Apr-08-08		rinus: <Tabanus> Without engines! http://eu.art.com/asp/sp-asp/_/PD--...

Apr-08-08		karnak64: <Nightranger>: I need nothing beyond my ex-wife to prove the "Women are Evil." <Tabanus>: your galleries are cool beans! The print of "Chess and a cordial" epitomizes my idea of the good life. Sign me up!

Apr-08-08		YouRang: <karnak64: <Nightranger>: I need nothing beyond my ex-wife to prove the "Women are Evil."> The old "proof by example"? :-)

Apr-08-08		YouRang: I suppose that 40...Nd3 shouldn't be a surprise. Freeing the knight would appear to be the point of sticking his rook on a6.

Apr-08-08		chesscard: 40... Nd3! is very interesting. 40... Nd3! 41. Rb1 c5!? (41...Nb4!? also is interesting) This is not a clear win.

Apr-08-08		Tabanus: Here's four more I found :) http://www.chesscentral.com/art-che... http://www.chessprints.com/Images/P... http://www.redbubble.com/img/art/si... http://render-2.snapfish.com/render...

Apr-08-08		DanLanglois: <chesscard: 40... Nd3! is very interesting. 40... Nd3! 41. Rb1 c5!? (41...Nb4!? also is interesting) This is not a clear win. > there's mountains of 40...Nd3 analysis on dalbertz forum

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