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Jul-01-18 | | Walter Glattke: CG surely tested 43.-Rb3 with the computer, but I don't know the answer. |
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Jul-01-18 | | Walter Glattke: 44.Qxb3 Qa8 45.Rxe4? Qxe4+ 46.Kg1 Nh3# / 45.N1e3? Nf2++ 46.Kg1 Nfh3+ 47.Kf1 Qf3# /
45.Qf7+ Nxf7 46.Rxe4 Qxe4+ 47.Kg1 Kg6 48.N1e3 Nh6 black wins. |
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Jul-01-18 | | Mayankk: Too many horsey moves to figure out what’s going on. The long diagonal is the key of course, but do I understand anything more? I will be lying if I say I do. |
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Jul-01-18
 | | agb2002: Black is one pawn down.
White threatens Rxe4.
The position of the white king suggests 43... Rb3: A) 44.Qxb3 Qc6 (threatens mate in two)
A.1) 45.N1e3 Nxg3+ 46.Kg1 Nh3#.
A.2) 45.Kg1 Nh3+ 46.Kg2 (46.Kh1 Nxg3#) 46... Nd2+ and mate in two. A.3) 45.h3(4) Nf2+ 46.Kg1 (46.Kh2 Qh1#) 46... Ngh3+ 47.Kh2 Qh1#. A.4) 45.Rxe4 Qxe4+ and mate in two.
B) 44.Qd5 Rb5
B.1) 45.Qc4 Qa8 looks similar to previous lines. B.2) 45.Nd6 Nxd6 (45... Rxd5 46.Nxe8 Re5 47.Nf6+ wins for White) B.2.a) 46.Qxd6 Qa8+ and mate in three.
B.2.b) 46.Qd3+ Kg7 47.Qd4+ Kg8 - + [n vs P].
C) 44.Nd6 Rxb7 45.Nxd8 Rxe7 46.Nf6+ (46.Nd6 Nxg3+ followed by Rxe1) 46... Kg6 47.Nxe4 Rxe4 recovers the pawn with a better ending due to the position of the kings. |
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Jul-01-18 | | malt: 43...Rc7 looks a nifty move,
(44.Q:c7 Nf2+ 45.Kg1 Ngh3+ 46.Kg2 Qa8+)
or
[45.Kg2 Qa8+ 46.K:f2 Qf3+ 47.Kg1 Nh3# ]44.Qb2 threatens mate ...Rc3 45.Nd2 Qc6
as far as I got |
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Jul-01-18 | | Walter Glattke: A5) 45.Qf7+ Nxf7 46.Rxe5 later mate, but hopeless. |
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Jul-01-18 | | patzer2: As <chessgames.com>'s posted Informant analysis from Sep 24, 2006 indicates, the solution to today's Stunday puzzle is 43...Rb3!! Black missed this winning move not once but three times. In a short span, Black missed the opportunity to establish the identical winning position with 43...Rb3!!, 45...Rb3!! and 47...Rb3!! Overlooking the winning 43...Rb3, 45...Rb3!! and 47...Rb3!! +- (-2.05 @ 43 ply, Stockfish 9 analysis of move 47...?), and not wishing to give White a draw by three-fold repetition with 47...Rc7 = (repeats the position after 43...Rc7 and 45...Rc7), Black blundered with 47...Rc2?. After 47...Rc2?, White missed the winning shot 48. Rxe4! +- (+12.47 @ 33 ply, Stockfish 9 analysis of move 48.?). Instead of punishing 47...Rc2? with 48. Rxe4! +-, White returned the favor with the mistake 48.Qxa7? which gifts Black a mate-in-five after 48...Nf2+! 49. Qxf2+ (49. Kg2 Qc6+ 50. Re4 Qxe4+ 51. Kg1 Ngh3#) 49...Qa8+ 50. Re4 Qxe4+ 51. Qf3 Qxf3+ 52. Kg1 Nh3#. Black did not see the mate-in-five with 48...Nf2+!, but instead played 48...Rb2 49. Qa6 Nf2+ -+ (-2.14 @ 44 ply, Stockfish 9 analysis of move 50.? which still wins but with more difficulty. P.S.: I missed 43...Rb3!! twice myself, once when it first appeared here on Sep 24, 2006 and again today. Maybe others find it easy the first or second time around, but for me (43...?, 45...? or 47...?) is an extremely difficult postion. |
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Jul-01-18 | | patzer2: Actually, White missed the chance to claim a three-fold repetition after 46...Rc3 =. According to the game note that appears on my screen here at <chessgames.com>, the draw was claimable for White all the way up to White's last move of the game but was not claimable after the checkmate on Black's last move. However, that does not appear to be in accord with FIDE rule 9.2 at https://www.fide.com/FIDE/handbook/.... <The game is drawn upon a correct claim by the player having the move, when the same position, for at least the third time (not necessarily by a repetition of moves): a. is about to appear, if he first writes his move on his scoresheet and declares to the arbiter his intention to make this move, or b. has just appeared, and the player claiming the draw has the move.> According to the USCF official rules at http://www.uschess.org/content/view... <Three-fold repetition is when a position occurs three times in the same game. The repetition does not have to be consecutive. The draw should be claimed by the player who wants a draw, before making her move. The player should stop the clock, call the T.D over and inform him that the move she is about to make will result in a three-time repetition. Most of the time, players agree to a draw in anticipation of three-fold repetition without the help of a T.D.anticipation of three-fold repetition without the help of a T.D.> Seems a stretch of the rule to say the draw is claimable all the way up until the end of the game, especially if it has been many moves since the draw by repetition. |
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Jul-01-18 | | patzer2: To clarify, White could have claimed the draw by repetition by writing 47. Qb7 on his score sheet and, without touching the Queen to make the move, declaring the draw because of his intention to play 47. Qb7. If the opponent had disputed the claim, White could have called the TD over to verify the move he was about to make (i.e. 47. Qb7) would repeat the position for a third time after 45. Qb7 and 43. Qb7. |
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Jul-01-18 | | Marmot PFL: Very complicated, first plan was 43...Nf2+ 44 Kg2 Rc2 but 45 Ne3 and Kf1 seems to refute this. 2nd I thought to divert the queen with 43...Rc7 44 Rxc7 Nf2+ 45 Kg2 Qa8+ 46 Kxf2 Qf3+ but missed 44 Qb2. |
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Jul-01-18 | | ChessHigherCat: What everybody else who didn't get it didn't say. |
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Jul-01-18 | | PJs Studio: Daaaaaaamn! Nice pressure. I feel so dumb just looking at Sunday puzzles |
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Jul-01-18 | | 5hrsolver: At least I got 43...Rb3
But this is all I analyzed.
43...Rb3 44. Qxb3 Qa8 45. Kg2 Nc3+ 46. Kf2 Qf3+ 47. Kg1 Nh3# |
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Jul-01-18 | | landshark: I haven't even followed the rest of it yet but have to say 43... Rc7 is a crazy move. Glad I didn't waste too much time finding that one. |
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Jul-01-18 | | lasker27: I see, thanks to Crafty, why 44 Qxc7 can't be played, but after 47 .. Rc2, what about 48 Rxe4 Nxe4 49 Qe4, threatening 50 Nd6+? Or if 48 .. Rc1 49 Rf4 again threatening Nd6? |
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Jul-01-18
 | | Breunor: lasker27 it looks like 48 Rxe4 wins:
Stockfish has:
1) +12.47 (33 ply) 48.Rxe4 Nh3 49.Rd4 Re2 50.Rd2 Re5 51.N1e3 Rb5 52.Qe4 Ng5 53.Qd3 Re5 54.Nd6+ Qg6 55.e8=Q Rxe8 56.Nxe8 Qxd3 57.Rxd3 Ne4 58.Rd4 Nc5 59.Nf6+ Kg7 60.Rd5 Nb3 61.Nxh5+ Kf7 62.Rd7+ Ke6 63.Rxa7 Kd6 64.Nxg4 Nd4 65.Nf4 Nc2 66.Kg2 Kc6 67.Ne5+ Kb6 68.Ra8 Kb7 69.Ra4 Kb6 70.Nd5+ Kb5 71.Ra8 Nd4 72.Nf4 Kb6 It looks like a win was missed on move 39, black had a chance to take the diagonal: 1) -5.35 (36 ply) 39...Qc6 40.e7+ Kh7 41.Ng2 Rf3 42.e8=Q Qxe8 43.Nd2 Nf2+ 44.Kg1 Nd3 45.Qb1 Qc6 46.Nf4 Kh6 47.Qa1 Nxe1 48.Qh8+ Nh7 49.Qe5 Qb6+ 50.Kh1 Nf6 51.Qxe1 Rc3 52.Qe2 Qc6+ 53.Kg1 Qc5+ 54.Kh1 Rxa3 55.Nf1 Ra1 56.Nd3 Qc6+ 57.Kg1 Ne4 58.Qe3+ Kg7 59.Qe2 Qb6+ 60.Nf2 Qxf2+ 61.Qxf2 Nxf2 62.Kxf2 Ra2+ 63.Ke3 Kf6 64.Nd2 a5 65.Ne4+ Kf5 66.Nd6+ Ke6 67.Nb5 Rxh2 68.Kd4 But after 39 Qe8, white missed a win with 40 e7: +2.59 (20 ply) 40...Kg7 41.Qb2+ Kf7 42.Nf5 Nc3 43.Re5 Kf6 44.Nd6 Rxd6 45.Qxc3 Re6 46.Rd5+ Kg6 47.Qd3+ Kh6 48.Ne3 Qg6 49.Nf5+ Kh7 50.e8=Q Rxe8 51.Rd7+ Nf7 52.Rxf7+ Qxf7 53.Nd6+ Qg6 54.Qxg6+ Kxg6 55.Nxe8 Kg5 56.Nd6 h4 |
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Jul-01-18 | | saturn2: A remark to the opening. In the 1..c5 variation instead of 3 c4 I like 3 Nc3 followed by e4 and Bc4. |
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Jul-01-18
 | | Richard Taylor: My choices were 43....Rb3 or 43...Rc7. It was difficult to see how to get the Q on a8 unless White cooperated but I thought that was the key with checks by the Ns and sometimes a N sac on b3 and a mate... and saw some winning ideas but left it. It appears as though 43. ... Rb3 is best and wins. So de facto I solved it... |
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Jul-01-18
 | | Richard Taylor: 43...Rc7 is an error but has a similar idea to 43....Rb3 |
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Jul-01-18
 | | Richard Taylor: <Mayankk: Too many horsey moves to figure out what’s going on. The long diagonal is the key of course, but do I understand anything more? I will be lying if I say I do.> You understood enough. That is the key. You somehow need a mate with the horseys! So I decided that I (I mean I as in I not the GM playing Black) needed to sacrifice the R to divert the Q and get mine on a8....(I wasn't sure whether c7 or b3) then I saw that in certain variations with the Q on a8 White couldn't avoid mate. I had to watch out for mate myself. And I was working out defensive sacs by White. But indeed there are so many moves it is hard to calculate and hard to settle on Rc7 or Rb3...I wavered over that. But I was getting tired for my 70 year bones and retired to bed. Indeed I had had the right idea and worked on only those two moves.... The horseys (Jan Gustafsson calls them that!) enable double checks. With double checks you can allow a Q by White and sometimes still check mate and so on. |
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Aug-22-18 | | sfm: Thanks for interesting analysis.
Very difficult game.
As for claiming draw, <Patzer2> gives the correct rules, which are critical to know: A 3-fold repetition draw must be claimed *BEFORE touching any piece*, otherwise there is no claim.
So, don't play a move and say "Hah! Repetition! Draw!" Nope! There are two more cute additions:
1) The player to move must be the same in all repeated positions. (Of course!) 2) The position is only regarded as repeated if the player to move can make the same moves in all 3 positions. I recall only two situations where this might not apply: the right to castle might have gone, and also the right to capture a pawn en passant. At least, that was how it was 40 years ago when I got my TL license. I thinnk I never used it, still knowing the rules was valuable along the way. |
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Aug-22-18 | | hdcc: It took a while for the penny to drop: the black queen wants to get onto the diagonal, which calls for the obvious move Rb3. I knew that was the solution, and didn't bother calculating any further (too much blitz chess has made me a little lazy). |
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Aug-22-18
 | | beenthere240: This was more of a Monday IMO. |
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Aug-22-18 | | cormier:  click for larger viewAnalysis by Houdini 4
9...Nc6 10.Nxe6 fxe6 11.Nc3 Qe7 12.Bf4 Rad8 13.Qd2 Ng4 14.h3 Nge5 15.b3 Nf7 16.Rad1 Nd4 17.Qd3 Ne5 18.Qe3 a6 19.Ne4 Qc7 20.Bg5 Rc8 21.Qd2 b5 22.f4 Nec6
+ / = (0.38) Depth: 23 |
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Aug-22-18 | | cormier: 1401: i - Houdini 4 Pro w32, 9s/Move inc
 click for larger viewAnalysis by Houdini 4 Pro w32: d 26
1. = (0.13): 7...Ng4 8.h3 Ne5 9.Nxe5 Bxe5 10.Qc2 Bg7 11.Nc3 a6 12.Bd2 Nd7 13.a4 b6 14.Ne4 Nf6 15.Bc3 Bd7 16.b3 Nxe4 17.Bxg7 Kxg7 18.Qxe4 Qc7 19.Qd3 f6 20.Rfe1 Rg8 21.e4 Rad8 22.Qd2 Rgf8 23.a5 2. = (0.14): 7...Nbd7 8.Nc3 Ng4 9.h3 Nge5 10.Nd2 Nb6 11.Qb3 a5 12.a4 Ned7 13.Nb5 Nb8 14.Ne4 Na6 15.Bd2 Nb4 16.Bc3 Bf5 17.Rad1 Rb8 18.g4 Bd7 19.Bxg7 Kxg7 20.Ra1 Bxb5 21.Qc3+ Kg8 22.axb5 Nd7 23.Rfd1 Qc7 |
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