buckmeister has kibitzed 8 times to chessgames

Feb-02-25 Shirov vs D Reinderman, 1999    buckmeister: It�s a variant of the �Greek Gift� which requires h7 only defended by the K. After Bxh7, followed by knight check, which usually makes way for the Q to infiltrate on h5 (this time h4). Nice work by Shirov.      May-13-24 M Ardaman vs M K Wong, 1984    buckmeister: Like Lambda I too found a solution starting Rf4: 27. Rf4+ Nxf4 28. Qe5+ Kg6 29. Qf5+ Kh6 30. Bxf4+ Qxf4 31. Qh5# OTB the first forcing mate is best, though not as elegant.      Feb-05-24 W Hug vs M Quinn, 2008   buckmeister: After 38. Rxe5 Qxe5, there are those who would say the queen is lost. But you don�t have to look much deeper to see that ignoring the queen leads to a quick mate. 39. Bf6+ Kf8 40. Qg7+ Ke8 41. Qh8+ Bg8 42. Qxg8#.      Jan-15-24 J Bellin vs Smejkal, 1965    buckmeister: RTSQS?      Jan-02-24 A Aleksandrov vs D Reinderman, 1992    buckmeister: If you find the forced mate (Rh7 etc), you need look no further. Whereas the Qh4 line requires a bit more work to be sure it works.      Oct-19-23 G Kantor vs M Warmerdam, 2022    buckmeister: JR I agree! Here�s one possibility: 23...Rxg2+ 24. Qxg2 Rg8 25. Bg4 Nxe3 26. fxe3 Bxg4 27. hxg4 Rxg4 28. Qxg4 Qxg4+ 29. Kh1 Qh3+ 30. Kg1 Qh2# There are many others, but none quite so elegant as the game continuation.      Aug-02-21 Robatsch vs A Kostjoerin, 1960    buckmeister: White can win the Black Q for a B with 28. BxRh8 Kxh8 29. Qe5+ K(any) 30. Ra3. Tough for a Monday but many good solutions in the end.      Dec-21-20 R Kempinski vs R Slobodjan, 2010    buckmeister: I found 31.hxg5 also works. If 31..Qxc7 32.Qh5+ Kg8 33. g6 (any) 34.Qh7#. Else if 31..Bxg5 32.Qxd6 wins the black Q.

indicates a reply to the comment.

You are not logged in to chessgames.com. If you need an account, register now; it's quick, anonymous, and free! If you already have an account, click here to sign-in.