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| Apr-07-09 | | UnsoundHero: White's game isn't all that bad. He just needs to avoid the cheapo ...Rd2+! He should start by playing 31 Rcc2. Black has little choice but to guard his Pe4 with 31...Re8. Now 32 Rcd2 controls an important file. Then 32...Rc7 33 Rd4 Rce7 looks equal. |
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| Apr-07-09 | | UnsoundHero: In this game, the defending rook was deflected off of the second rank. But the most common case is where the defending rook is deflected off of the back rank. Here are some examples: Timman vs Yusupov, 1987
29 Re8+ is a classic "back-rank spank" by Timman! Yusupov's back rank was too weak because it was too strong! The most classic "spank" of all time would have occured in the game R. Byrne-Fischer: R Byrne vs Fischer, 1963
However, after 21...Qd7, R. Byrne decided to cheat history, and resigned with dignity, before Fischer could spank him with 22 Qf2 Qh3+ 23 Kg1 Re1+! 24 Rxe1 Bxd4 forcing mate. |
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| Apr-07-09 | | whiteshark: <31...Rd2+ 32.Rc2 Qxc3+> shows that ♙c3 protection was an illusion. |
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| Apr-07-09 | | agb2002: White is a pawn ahead and threatens 32.Qxe5 and the pawn on b7. However, Black can fork the king and the rook on e2 with 31... Rd2+: A) 32.Rxd2 Qxe4 - +.
B) 32.Ka3 Ra5+ 33.Qa4 (33.Kb4 Qc5#) Rxa4+ and 34... R(Q)xe2 - +. C) 32.Ka1 Rxc3 (or 32... Rxe2 - +)
C.1) 33.Qxe5 Rxc1#.
C.2) 33.Rxc3 Qxc3+ 34.Kb1 Qb2#.
C.3) 33.Rxd2 Rxc1#.
C.4) 33.Qd5+ Qxd5 34.Rxc3 (34.Rxd2 Rxc1+ 35.Kb2 Qxd2+) Rxe2 - +. C.5) 33.Qc4+ Rxc4+ and mate in two.
C.6) 33.Kb1 Rxc1+ 34.Kxc1 Qb2#.
D) 32.Kb1 Rxe2 - +.
E) 32.Rc2 Qxc3+
E.1) 33.Ka3 Ra5+ - +.
E.2) 33.Kb1 Rd1+ 34.Rc1 Qxc1#.
E.3) 33.Kc1 Qxc2+ 34.Qxc2 Rcxc2+ 35.Kb1 Rxe2 and mate soon. E.4) 33.Kc1 Rxe2 is slower but interesting
E.4.a) 34.Rxc3 Rxc3+ and next Black grabs the queen.
E.4.b) 34.Qc4+, Qd5+, Qe6+ Black takes the queen and ends up a rook ahead at least. E.4.c) 34.Qxe2 Qa1+ 35.Kd2 Rxc2+ 36.Kxc2 Qxa2+ 37.Kd1(3) Qxe2+ 38.Kxe2 Kf7 winning the pawn endgame. Let's see. |
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| Apr-07-09 | | Samagonka: Easier than yesterday's. The pinner is the winner. |
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| Apr-07-09 | | MrPooter: Can someone explain why Kc1 is not a reasonable escape here? |
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| Apr-07-09 | | Babar47: MrPooter: just above your head, in the sky......
agb2002 already provided the line
E.3) 33.Kc1 Qxc2+ 34.Qxc2 Rcxc2+ 35.Kb1 Rxe2 and mate soon |
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| Apr-07-09 | | zb2cr: According to the <chessgames.com> database, Mieses lost to Breyer quite frequently. When he saw Breyer play 31. ... Rd2+, Mieses must have thought: "Oh no, he's doing it to me again!" |
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| Apr-07-09 | | gtgloner: 31. ... Rd2+ looks interesting. Played through some lines in my head and I don't see any escape for white. Let's see. |
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| Apr-07-09 | | eblunt: <Dechiel 33 Ka3 Rxc2 and black picks up a rook, > I might be going mad, but doesn't that give white 34. Qe8+ and mate soon after ? black needs to play Ra4+ first, which picks up the Queen anyhow |
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| Apr-07-09 | | Alphastar: <SuperPatzer77: Take a look at my first commentary below: 32...Qxc3+! 33. Kc1 Qxc2+! 34. Qxc2 (forced) Rcxc2+ (not 34...Rdxc2+??, 35. Rxc2 Rxc2+, 36. Kxc2 =), 35. Kb1 Rxe2 (Black wins two rooks and eventually mates with two rooks). SuperPatzer77>
Actually the pawn endgame after 34...Rdxc2+? 35. Rxc2 Rxc2+ 36. Kxc2 is not equal but easily won for black, but an extra rook is ofcourse easier to exploit. |
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| Apr-07-09 | | CHESSTTCAMPS: It may not appear from a logical standpoint that black should have any advantage in this position. White is actually a pawn up and his king has one more pawn of shelter than the black king. Yet black has a demonstrable forced win from the puzzle position. Why? Because black has more actively placed major pieces and there are hidden weaknesses in the white camp. In the end, it all boils down to tactics: 31.... Rd2+!
Principal white weakness: an overloaded rook on e2 that can't move because is protecting the queen on e4. Black's move is a deflection sacrifice that has come to be named the "hook and ladder" trick. Because it has received much attention recently (and it is a tactic with a very productive history of winning games), I found it right away. 32.Rc2
This rook is now overloaded. If 32.Kg1 Rxe2 wins a rook. If 32.Rxd2 Qxe4 wins a queen for a rook. 32.... Qxc3+!
2nd white weakness: underprotected c-pawn. Not 32...Rxe2? 33.Qxe2 and white survives. Now white can resign, because 34.Kc1 Qa1#, 34.Ka3 Ra5+ costs the queen, and 34.Kb1 Rd1+ is mate next move. Nice variation on the typical "hook and ladder" which usually occurs on the back rank. |
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| Apr-07-09 | | CHESSTTCAMPS: Yikes - I guess I am at least the 3rd person to "see" 34...Qa1#. Substantially reduced credit, i.e. 1-0 instead of 0-1? |
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| Apr-07-09 | | Alphastar: <CHESSTTCAMPS> That'll be 20 rating points, please |
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| Apr-07-09 | | geeker: Obvious, but a very pretty pattern. |
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| Apr-07-09 | | CHESSTTCAMPS: <Alphastar: CHESSTTCAMPS That'll be 20 rating points, please> I don't know, maybe I get away with it - Mieses resigned before I committed my blunder. :) |
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| Apr-07-09 | | Eduardo Leon: 31. ... Rd2+
It's obvious that 32. Rxd2 Qxe4 wins, and 32. K(any) Rxe2 wins too, so white is forced to reply... 32. Rc2 Qxc3
Ouch. The rook is pinned. Now, retreating to the first rank loses outright, so white is forced to reply... 33. Ka3 Ra5+
Of course, not 33. ... Qxc2?? or 33. ... Rxc2?? and white gets away with a perpetual with 34. Qe8+. Now, white must stop the check with the queen, therefore losing it. 34. Qa4 Rxa4+ 35. Kxa4 Rxc2
Now that white doesn't threaten any perpetual, black can take the rook. |
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| Apr-07-09 | | Patriot: 31...Rd2+ is a common tactic ("removal of the guard") that didn't take me long to spot. This theme comes up often on chess.emrald.net. 32.Rcc2 (Forced--otherwise 32...Rxe2)
32...Qxc3+ 33.Kb1 (33.Kc1 Qxc2+ 34.Qxc2 Rcxc2+ and 35...Rxe2) Rd1+ 34.Rc1 Qxc1# |
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Apr-07-09
 | | sbevan: got it! looked at Qxc3+ first, then it clicked. |
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| Apr-07-09 | | SuperPatzer77: What some chess folks must have overlooked after 32...Qxc3+! is 33. Kc1 Qa1+??? (not mate), 34. Kxd2 (that costs Black a rook). They must have missed 33...Qxc2+!, 34. Qxc2 (forced) Rcxc2+, 35. Kb1 Rxe2 - Black wins so easily with two rooks up and mates soon. 0-1 SuperPatzer77 |
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| Apr-07-09 | | dzechiel: <Peter Nemenyi: Two posters have now given 33...Qa1#, which doesn't work because the Black R at d2 is unprotected and the White K can take it.> I'm embarrassed to say that one of them was me. <sigh> |
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| Apr-07-09 | | xrt999: < eblunt: <Dechiel 33 Ka3 Rxc2 and black picks up a rook, >
I might be going mad, but doesn't that give white 34. Qe8+ and mate soon after ? black needs to play Ra4+ first, which picks up the Queen anyhow> do you mean Ra5+? |
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| Apr-07-09 | | kevin86: A much better and easier puzzle than yesterday's.
The key move 31...♖d2+ is obvious. The twist comes after the seemingly saving move of 32 ♖c2,but the thrust of ♕xc3+ smashes the white position to small pieces. |
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| Apr-07-09 | | agb2002: The fact that three strong regulars tried the same move 34... Qa1# cannot be a mere coincidence but a clue of the existence of a baleful influence (just paraphrasing http://www.cs.berkeley.edu/~wkahan/...) of CG's rating (stars) upon the kibitzer skills. Let A be the event that the kibitzer makes a mistake at (as soon as) the fifth ply, B the event that the kibitzer is influenced by CG's rating and C its complementary event, that is to say, the kibitzer is not influenced by CG's rating. Then, if we can estimate the probability of B, C, A/B, that is, the event of making that mistake under the influence of the assigned rating, and A/C, the event of making that mistake due to other causes, it is possible to work out the probability of B/A, the event of being under the influence of CG's rating knowing that the mistake was made by applying Bayes' theorem:
P(B/A) = P(A/B)*P(B) / [P(A/B)*P(B) + P(A/C)*P(C)]
I've tried a few estimates and always had a result very close to 1. (No criticism against CG intended, just trying to understand curious facts). |
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| Apr-07-09 | | xrt999: after 33.Ka3 Rxc2 34.Qe8+ Kh7 35.Qg6 Kg8 (or Kh8) 36.Re8 is indeed checkmate.
So, as you point out, 33...Ra5+ and white has no other move than 34.Qa4 Rxa4 35.Kxa4 Rd4+ |
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