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< Earlier Kibitzing · PAGE 667 OF 963 ·
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Dec-24-10
 | | Domdaniel: <MAJ> I suspect those 15 consecutive captures were noted somewhere by those who keep track of these things, if not by Tim Krabbe. At that time, the brute-force route wouldn't even have occurred to me. And a Happy Christmas to you too. |
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| Dec-24-10 | | MostlyAverageJoe: <Domdaniel: Another record -- you're the only person to win a physical object in each of the 4 years.> Nope, I did not: 2008/2009 gave me only extra premium membership... |
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| Dec-24-10 | | MostlyAverageJoe: BTW, speaking of records, <The HeavenSmile> should be noted for the record of getting 3 premium prizes in one year (and all, initially, were identical :-). While <cu8sfan> and myself also got 3 each, they did not come in the same year for either of us. Not that many people got two premium prizes, either; only yourself and <Kvasir>. Also, <cu8sfan> holds the distinction of grabbing 2 consecutive premium prizes. |
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Dec-24-10
 | | SwitchingQuylthulg: Call me antiquated, but I still believe the single strongest weapon any holiday contestant can hope for is none of <Mostly>'s little programs but rather LIST.COM, trusty companion of DOS users worldwide for gods only know how long. ;-) |
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| Dec-24-10 | | WinKing: Just stopped by to wish you Happy Holidays <Domdaniel>! Thanks for all your help & advice it the 'World Team' encounter. We need more 'gurus' of the game such as yourself. |
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Dec-24-10
 | | Domdaniel: Oops, I just made 16,000 posts ... |
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| Dec-24-10 | | hms123: <Dom>
Did you know that the square root of 16,000 is 126.4911064? Well, sort of. (<dak> There's a trick to this as well.) |
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Dec-24-10
 | | Domdaniel: <hms> yep, 5^3 x 2^7 is ... hang on, those exponents are *odd*. No fair, even if I know root two to n places ... |
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Dec-24-10
 | | Domdaniel: At least 16001 is prime. You know where you stand with primes. And, um, the sum of the squares of 25 and 124, I think. |
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| Dec-24-10 | | hms123: <Dom> You have sent me down memory lane. I used to remember phone numbers by things like log(5) =6990 (the local theatre--we only had one exchange in those days). Four decimal places was my limit. That was all I needed. Odd how some things stick. |
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Dec-24-10
 | | Domdaniel: Here's a trick number question. 16001 is prime (of the form 4n+1, which is crucial). There exists some other number, call it 'n', such that n times 16001 is one greater than a perfect square, ie 16001 x n = m^2 + 1. Actually, there are an infinite number of values that n can take. But I can see the smallest one, just by looking at data already given ... |
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Dec-24-10
 | | Domdaniel: Ah, the number madness...
The answer is 26. Sum of the squares of 5 and 1. Because 5 x 25 = 124 + 1. |
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Dec-24-10
 | | Domdaniel: Right, no more squares.
As the remaining time shrinks, the coming clues get easier. I suggest, first, a 'somethingest player ever' which will take between zero and five minutes, followed by a numerical clue that takes no time at all. Christmassy links are possible. |
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Dec-24-10
 | | Annie K.: <hms: <<dak> There's a trick to this as well.>> <dakkie> is not here right now, can I take a message? ;p Season's Greetings,
Shirley Yanno
Procrastinators' Club
Intermittent Secretarial Division |
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Dec-24-10
 | | Domdaniel: <hms> Four places? Bet you was weaned on log books ... |
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| Dec-24-10 | | hms123: <Dom> I used to be up on number theory, but this one escapes me. I realize that it has to do with Fermat, but that's all that's left. What do you see? |
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| Dec-24-10 | | hms123: <clue alert> |
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Dec-24-10
 | | Annie K.: How long ago did I say "within two hours or so"? ;) |
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Dec-24-10
 | | Domdaniel: Another man down. Late rush from BVer - two in succession *and* five for the year. |
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Dec-24-10
 | | OhioChessFan: I am sure I'm not the only one who thought immediately it was a Petrosian anagram. Henderson.......oops, clue already solved. |
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Dec-24-10
 | | Domdaniel: <hms> - <what do you see?>
The numbers 25 and 124, and the fact that 5 times the 1st exceeds (one time) the other by 1. Add the squares of 5 and 1 to get 26. But it works with any prime of the form 4n+1. Take, say, 73: sum of squares of 8 and 3. Multiply 3 by 3 to get (8+1). Find sum of squares of the multipliers, 3 and 1.
10 x 730 = 729 + 1 = 27^2 + 1.
Trivial stuff, rilly.
I was looking for Petrosian vs Porcherdesh ... or something ... and I was about to try variations on the klu words, eg 'sure' for 'certain'. No hope. |
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Dec-24-10
 | | Check It Out: Merry Christmas, <DomDaniel>, keep up those great lexicologicalwhatchamacallit posts! |
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Dec-24-10
 | | Domdaniel: Well, I predicted the format wrongly *again*. Apart from its Christmas theme. Go memorize some hymns, ye heathens. |
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| Dec-24-10 | | crawfb5: I had looked at some <Lukes> and was just about to try some <Noels> when it was solved. |
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| Dec-24-10 | | hms123: <Dom> Thanks. That's a new one for me. And, wow, did that clue go fast! |
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