Abdel Irada: ∞
[Part 2 of 2]
2.1.1.2) A better move, to my mind, is <14. ...Ne4!>. (The rook is immune: 15. Kxe2?, Nc3++ wins the queen.)
Now Black threatens 15. ...Nxf2+ and 15. Be3? loses the queen to a knight fork, so there's only one way to defend: <15. Be1...>
2.1.1.2.1) But now this bishop is overburdened, and e1 is no longer available for the rook, so how about <15. ...Rxf2!>, when White can't take because of that pesky fork on c3.
Also, Black now threatens both a queen incursion on e2 with check and the simple capture of the undefended bishop on g2.
This forces <16. Rg1>, when Black wraps up with a combination: <16. ...Nc3+ 17. Bxc3, Qe2+ 18. Kc1, Qe3+ 19. Bd2...> (19. Nd2, Qxc3+ 20. Qc2, Qxd4 21. Qb2 [or 21. bxa6, Rxd2!] Qxb2 22. Rxb2, Bb7
) <19. ...Rxd2! 20. Nxd2▢, Qxg1+ 21. Bf1...> (or 21. Kc2, Qxg2 22. bxa6, Qe2
), <Bb7
>.
There are still moves to be made, but there is no reason why Black should not be able to win with his three-pawn advantage and safer king.
2.2) <13. Kf1, Qe8...>
Here White intends to maintain the defense of his f-pawn. But this involves dangers of its own.
His first problem is how to keep hold of his light squares, the key to them being the pawn on b5. We've already seen what happens if he allows them to be overrun.
2.2.1) As in the previous line, we begin with the defense of this pawn with <14. Rb1...>.
But dangers set in immediately with <14. ...Ne4!>.
2.2.1.1) As in line 2.1 above, the rook is immune because of <15. Kxe2, Nc3++ 16. Kf1, Bxb5+ 17. Qxb5, Nxb5
>.
This means something must be done about the threat of ...Nxd2, not to mention ...Rxf2+. And if the bishop leaves the a5-e1 diagonal, there is also ...Nc3.
2.2.1.2) The most consistent reply is <15. Be1...>, but this is a gossamer defense immediately torn asunder by <15. ...Rxe1+!>, and how is White to continue?
2.2.1.2.1) <16. Kxe1, Nc3+
>
2.2.1.2.2) <16. Nxe1, Nxd2+ 17. Kg1, Nxb1
>
2.2.1.2.3) <16. Rxe1, Bxb5+
>
White's only other alternative is to come to the aid of his bishop, at the cost of surrendering the b-pawn.
White has to do this with his queen; allowing 15. ...Bxb5 with his queen on a4 would be catastrophic.
2.2.1.3) The first and more active of two options is <15. Qd1, Bxb5 16. Kg1...> (not 16. Rxb5, Rxf2+ 17. Kg1, Qxb5
) <16. ...Nxf2 17. Qc1, Nd3
>, when Black wins whether White takes the queen off the back rank or not.
2.2.1.3.1) <18. Qc3, Rxg2+ 19. Kxg2, Qe2+ 20. Kh3, Bd7+
> leaves White's king walking to his death.
2.2.1.3.2) <18. Qf1, Rxd2!> and Black wins a piece thanks to the threat of 19. Nxd2? (or 19. Rxb5?), Qe3+ with mate in one.
2.2.1.3.3) <18. Qd1, Ba4 19. Qf1, Rxd2!
> transposes into a similar problem for White.
---
*Looking back over this long post, I find that the puzzle was a bit "insane" after all — but only in terms of volume of variations, not in theme. (Sufficient volume that I left this post half-composed and returned to complete it a day late.)
The *idea* for Black is very clear: White's light squares are weaker than they appear. If you exploit this weakness thematically, you will win.
∞