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Emil Davidovich Sutovsky vs Ivan Sokolov
9th Essent Hoogeveen (2005), Hoogeveen NED, rd 6, Oct-29
Spanish Game: Open. Bernstein Variation (C80)  ·  0-1



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sac: 51...Qd3 PGN: download | view | print Help: general | java-troubleshooting

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Kibitzer's Corner
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Premium Chessgames Member
  morfishine: <51...Qd3> and Black wins
Feb-11-16  frogbert: <CbtD: Notes on alternatives:  If 52 Kg3/h3, then 52 ... Qd3+ forces the fatal capture.>

After 51... Qd8+?! 52. Kg3! Qd3+ 53. Kf2, defending the rook, the initial 51... Qd8+ has only made the black win harder.

Feb-11-16  saturn2: After 51..Qd3 neither 52 BxQ nor Rf2 helps white. If two neighboring pawns are on the 6 th rank the rock cannot stop both of them. And the King is to far away to intervene.
Feb-11-16  Elrathia Kingi: From this position:

click for larger view

White could try:
54. Rxc3 d1=Q
55. Rf3

Now, black can try 55...Qxf3 56.gxf3 Kg7 57.Kxg5, which is a draw, but... 55...Qg1! looks like it will break down the fortress.

click for larger view

58.Kg3 or 58.Kh3 are both met by ...h4, and the king's days are numbered. (And that number is somewhere around 12.)

Feb-11-16  CHESSTTCAMPS: Black has a Q+3 pawns for R+B, a 3-point material advantage if evaluated traditionally, but actually much more given the advanced state of the passed c-pawns, even though they are doubled. Initially, I was looking for a queen transfer to the g-file, seeking Qg4#. Then I looked for a fork, but 51... Qd2?? 51.Rxd2 obviously does not work. However, that led me immediately to 51... Qd3!! and I knew I'd found a quick finish:

A. 52.Bxd3 cxd3 (a rook by itself can only defend 2 passed pawns on the 6th if it is on the move and attacking one of the pawns) 53.Re8+ Kf7 54.Rd8 c2 55.Rc8 d2 1-0

B. 52.Re8+ Kf7 53.Bxd3 (R moves Qxc2) cxd3 transposes to A.

C. 52.Rf2 (R other Qxc2) Qe3 53.Rf1/f3 Qd2 54.B moves c2 wins.

Feb-11-16  cocker: Strangely, the opening move is easier to spot than in some Monday/Tuesday puzzles. It just has to be 51 ... Qd3. Seeing through to the finish is a bit harder of course.
Feb-11-16  Nick46: I surprised (and surpassed) myself by finding 51... Qd3
Feb-11-16  zb2cr: A general principle, that when the defending King is not close, 2 connected passed Pawns on the 6th beat a Rook, guided me to the winning 51. ... Qd3!.
Feb-11-16  dfcx: black has queen agains R+B, and two passed pawns, a quick win is in sight with a promotion.

First looked at 51...Qd2? 52.Rxd2 cxd2 53.Kg5 and white wins.

The I found:


A. 52.Bxd3 cxd3 53.Rf2 (Ra2 c2) d2 and black will get a new queen soon.

B. 52.Rf2 Qe3 53.Rf3 Qd2 wins too

Premium Chessgames Member
  Once: Ooh, now that's interesting. Like nearly everyone else I patted myself on the back for finding 51...Qd3.

But as <Patzer2> has pointed out 51...Qd4 also wins.

click for larger view

It's actually quite a vicious little move. Black threatens Qxf4+/ Qg4+ and Qxe2. On 52. Kg3 h4+

click for larger view

And white is being slowly strangled. Black will march his king up the board and either give mate or gobble pawns and then give mate.

Fritzie is saying that 51...Qd4 is stronger than the game continuation of 51...Qd3. I'd be happy to find either over the board.

Premium Chessgames Member
  morfishine: All-in-all, quite an intriguing maneuvering game
Feb-11-16  BOSTER: What if after 51...Qd4 52.g3
Premium Chessgames Member
  patzer2: <Once> Just finished looking at 51...Qd4 with Deep Fritz 15. It does win, but it gets complicated after 51...Qd4 Kg3 52. h4+! Kf3 (diagram below)

click for larger view

when the computer indicates play might continue 53...Qd5+ 54. Kf2 Kg7 55. Re7+ Kf6 56. Re2 Kf7 57. Ke3 Kg6 58. Kf2 Kh5 59. Kg1 Kg4 60. Kf1 Qd7 61. Rf2 Qd4 62. Ba4 Qd3+ 63. Kg1 c2 64. Bxc2 Qe3 65. Kf1 Qc1+ 66. Ke2 Qxc2+ 67. Ke1 Qb1+ 68. Ke2 Qd3+ 69. Ke1 c3 70. Rf3 Qd2+ 71. Kf1 c2 72. Kg1 c1=Q+ 73. Kh2 Qdd1 74. Rf1 Qxf1 75. g3 Qf2#.

Seems to me 51...Qd4 is a move simple for a computer calculate, but not so easy for a human. Sokolov's 51...Qd3 52. Bxd3 cxd3 is, at least for me, a more practical solution.

Feb-11-16  BOSTER: This is the pos white to play 46.

click for larger view

After 46.a6 my guess white had draw.

Premium Chessgames Member
  kevin86: I had the right move, but at the wrong time. Black must first remove the white passed pawn BEFORE he sacrifices the queen.The two pawns will buffalo the rook and win in the end.
Premium Chessgames Member
  kevin86: No, I did get it right after all on the 51st move!
Feb-11-16  lentil: The solution was not difficult for me, except that I first had to eliminate the BLUNDER Qd2??, when after Rxd2 cd, the WB holds the pawns successfully, whereas after Qd3! BXd3 cd the WR fails to do so. It's a clear demonstration of the mutability of piece values.
Premium Chessgames Member
  Once: <Patzer2> Yes, I sure you are right. 51...Qd4 is one of those moves which is very easy for a computer but hard for a human. 51...Qd3 is a much safer bet.

What I found interesting was that 51...Qd4 was simultaneously very quiet and contained so many threats that white couldn't defend.

Premium Chessgames Member
  Jimfromprovidence: It's interesting that any non-blunder move wins for black, even 51...Kh8.

click for larger view

That's how bad white's position is.

Feb-11-16  Cheapo by the Dozen: <frogbert>:

Excellent point. Thanks!

Feb-11-16  mel gibson: I saw it in about 5 seconds but I needed longer to convince myself. 2 connected passed pawns on the 6th rank are super powerful.
Feb-11-16  Patriot: 51...Qd3 52.Bxd3 cxd3 is a familiar winning pattern. What's cool is 52.Rf2 Qe3 53.Rf1 Qe2 54.Rc1 Qd2. The queen dances in a square to win material.
Feb-11-16  stst: Got to let either pawn on c-file to promote, a Q-sac should do it:

52.Re8+ Kf7
53.Bxd3 c4xd3
54.Rd8 (or Rc8) d2 (or c2, actually doesn't matter)
Either pawn will promote and the rest should be easy.

(B) pretty much the same...
52.Bxd3 c4xd3
53.Re8+ etc etc follows (A)

Premium Chessgames Member
  transpose: I found this faster than I usually do for a Thursday puzzle.I might presume that this puzzle was misplaced, or I might presume that I am just getting stronger. But which? I shall presume the latter.

Excuse me while I go pour myself a celebratory glass of wine.

Premium Chessgames Member
  gawain: I liked the puzzle-ish solution with 51...Qd3 52 Bxd3 cxd3 and wins because the lone rook cannot cope with the connected passed pawns.

But what if 52 Rf2? Sure, Black wins with 52...Qe3 53 Rf3 Qe1+ 54 Rg3 K moves etc. but it is messy and tedious.

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